Fix LateInitializationError

✅ Solution

LateInitializationError usually occurs when a `late` variable is initialized more than once. To fix this, ensure that the `late` variable is initialized only once, often by checking if it's already initialized before assigning a value or moving the initialization to a single, controlled point in the code (like initState or within a specific conditional check). Consider using a nullable type with a default null value if the variable doesn't need immediate initialization.